A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.

`["Assume "pi=22/7]`

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#### Solution

Radius (*r*) of heap = (10.5/2)m = 5.25 m

Height (*h*) of heap = 3 m

`"Volume of heap "=1/3pir^2h`

`=(1/3xx22/7xx(5.25)^2xx3)m^3`

= 86.625 m^{3}

Therefore, the volume of the heap of wheat is 86.625 m^{3}.

Area of canvas required = CSA of cone

`=pirl=pirsqrt(r^2+h^2)`

`=[22/7xx5.25xxsqrt((5.25)^2+(3)^2)]m^2`

`=(22/7xx5.25xx6.05)m^2`

= 99.825 m^{2}

Therefore, 99.825 m^{2} canvas will be required to protect the heap from rain.

Concept: Volume of a Right Circular Cone

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